Pls answer this, i will need an explanation as well-.

Hello!

First you have to find the probability of picking the right numbers

To do this you do the amount of favorable outcomes over the total amount of outcomes

There are 5 favorable numbers and 18 in total

This is a probability of 5/18

For the second number there of 4 favorable numbers and 17 in total since you already picked one

This is a probability of 4/ 17

For the third number there are 3 favorable numbers and 16 in total

This is a probability of 3/ 16

For the fourth number there are 2 favorable numbers and 15 in total

This is a probability of 2/ 15

For the fifth number there are 1 favorable numbers and 14 in total

This is a probability of 1/14

To get the answer you multiply all the probabilities together

5/18 * 4/17 * 3/16 * 2/15 * 1/14 = 1 / 8568

The answer is 

Hope this helps!

The first one, i believe, would be correct. all the others have one thing in common, and that's that they have repeating numbers. in the second one, x and y have repeating 6's and 3's, and in the third, x and y have repeating 6's as well. in the last one, there are repeating 3's. the first one has no repeating numbers.