Solve the equation for x, where x is a real number (5 points): 3x^2 - 2x + 2 = 5

Subtract 5, then use the quadratic formula to find ths solutions.
  3x^2 -2x -3 = 0
  x = (-(-2) ±√((-2)^2 -4(3)(-3)))/(2(3))
  x = (2 ±√40)/6 = (1 ±√10)/3

The solutions are x = (1 ±√10)/3 ≈ {-0.720759, 1.387426}

Correct sir/miss have a good day x < 3