Which values of x will make the expression 6x^2-54/5x^2-20 equal to 0? check all that apply. −9 −3 −2 0 2 3 9

From the given expression:
(6x^2-54)/(5x^2-20)
simplifying the above we get:
[6(x^2-9)]/[5(x^2-4)]
=[6(x-3)(x+3)]/[5(x+2)(x-2)]
The expression will be 0 when the numerator is zero, thus given the numerator, the values that will make it 0 will be x=3 and x=-3
hence the answer is:
x=-3 and x=3

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