2. the sum of two integers is 74. the larger is 26 more than twice the smaller. find the two integers.

74=x+y is the equation at the beginning we will say that x is the smaller number and y is the larger one. Now we substitute the larger number (y) for 26+2x. Plug that into the beginning equation to get 74= x+ 26+2x. Now solve.
74=3x+26
48=3x
16=x
So we know that our smaller number is 16. To find the larger number we plug the value of the smaller number into the equation for the larger number like this.
y=26+2x
y=26+2(16)
y=26+32
y=58.
So to check our answer we can plug in both values into the beginning equation.
74=58+16
74=74.
So to sum this up the smaller number is 16 and the larger number is 58.

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