Which of these sets of side lengths are pythagorean triples? check all that apply. 10, 24, 26 14, 48, 49 9, 12, 16 9, 40, 41 15, 20, 25

The only sets of side lengths that are Pythagorean triplets are;

D: 9, 40, 41

E: 15, 20, 25

Pythagorean triplets is a set of three numbers such that the sum of the last 2 numbers is equal to the square of the first number. Examples are;

(3, 4, 5)

(5, 12, 13)

(7, 24, 25)

(9, 40, 41)

Now, for any of the given options to be regarded as a Pythagorean triplet, then each set must be a factor in the examples of Pythagorean triplets I listed.

From inspection, we can see that;

15, 20, 25 is a factor of (3, 4, 5) because 5(3, 4, 5) = (15, 20, 25)

Finally, (9, 40, 41) is also a Pythagorean triple as given in the examples earlier.

Read More about Pythagorean triplets at; link

since your problem is x^4 = 81, what you have to undeo is the "to the fourth power" part.

the inverse (opposite operation) of "to the fourth power" is "to the fourth root".

  (x^4) ^ ¼   = 81 ^ ¼  

  81 = 3^4     so (3 ^ 4) ^ ¼   =   3 ^ 1   = 3

by hand: (3 ^ 4) ^ ¼   =   3 ^ (4 x ¼) = 3 ^ 1   = 3   (when you take a power to a power, multiply the exponents.)

or, do it by calculator. one way of finding the fourth root is to use ^ (1/4)

step-by-step explanation: