Quadrilateral abcd is inscribed in this circle. what is the measure of angle b?

∠B = 132°

Step-by-step explanation:

Quadrilateral ABCD is inscribed in the given circle.

And if a quadrilateral is inscribed inside a circle then the quadrilateral is called cyclic quadrilateral.

And the sum of opposite angles of a cyclic quadrilateral is supplementary that is 180

⇒ Sum of opposite angles of the quadrilateral ABCD is 180

⇒ ∠A + ∠C = 180° and ∠B + ∠D = 180°

Now, ∠B + ∠D = 180°

⇒ 3x - 12 + x = 180

⇒ 4x - 12 = 180

⇒ 4x = 180 + 12

⇒ 4x = 192

⇒ x = 48

So, ∠B = 3x - 12

⇒ ∠B = 3 × 48 - 12

⇒ ∠B = 144 - 12

⇒ ∠B = 132°

let's solve your equation step-by-step.

4x+2=2x+12

step 1: subtract 2x from both sides.

4x+2−2x=2x+12−2x

2x+2=12

step 2: subtract 2 from both sides.

2x+2−2=12−2

2x=10

step 3: divide both sides by 2.

2x

2

=

10

2

x=5

step-by-step explanation:

i would need to see the dot plot : )