Aprior study estimated as 34%. the analysts would like to conduct a second study on the same topic with a margin of error, e, of 0.027 and a confidence level of 90% (z*-score 1.645). what is the minimum sample size that should be used so the estimate of will be within the required margin of error of the population proportion? n = (1 – ) • 17 23 430 833

833

Step-by-step explanation:

When the prior population proportion (p) is known , then the formula to find the minimum sample size is given by :-

where, is the z-score for confidence level (c) and   E = the margin of error .

Given : A prior study estimated as 34%.

i.e. p= 0.34

Confidence level = 0.90

Critical z-score for 90% confidence level :

Margin of error : E= 0.027

then , the sample size =

Simplify ,

Hence, the minimum sample size=833

80x^8−68x^6+16^5−20x^4−4x^3+8x^2

hope i'm right lol