1. use the babylonian method for your next estimate for the square root of 130 by using 11.4022 as your guess. what is your result? a) 11.4018 b) 11.3043 c) 11.6102 d) 16.1246 2. naila wants to use the babylonian method to estimate the square root of 58 to the neatest hundredth. her initial estimate is 7.8. what is her estimate after she correctly completes the babylonian method once? a) 7.43 b) 7.44 c) 7.61 d) 7.62 3. use the babylonian method for your next estimate of the square root of 115 by using 10.7262 as your guess. what is your result? a) 10.7238 b) 10.6107 c) 10.8393 d) 16.0869 4. kayla wants to use the babylonian method to estimate the square root of 43 to the nearest hundredth. her initial estimate is 6.9. what is her estimate after she correctly completes the babylonian method once? a) 6.44 b) 6.57 c) 6.45 d) 6.56fast need the answers asap

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graphically?   well, you graph them both, the solutions is where they both intersect each other, since there are two solutions, meaning they will meet twice, or namely the linear will run into the quadratic curve twice, and where they meet, those x,y coordinates are the solutions to the system.

a.   we have two

lines:   y = 4-x   and  

y = 8-x^-1

given two simultaneous equations that are both to be

true, then the solution is the points where the lines cross. the intersection is

where the two equations are equal. therefore the solution that works for both

equations is when

4-x = 8-x^-1

this is where the two lines will cross and that is the

common point that satisfies both equations.

b.   4-x = 8-x^-1

  x           4-x       8-x^-1

-3           7        

8.33

-2           6         8.5

-1           5         9

  0           4        

-

  1           3        

7

  2           2        

7.5

  3           1         7.67

the table shows that none of the x values from -3 to 3 is

the solution because in no case does

4-x = 8-x^-1

to find the solution we need to rearrange the equation to

find for x:

4-x = 8-x^-1

multiply both sides with x:

4x-x^2 = 8x-1

x^2+4x-1=0

x= -4.236, 0.236

therefore there are two points that satisfies the

equation.

find y:  

x=-4.236

y = 4-x   = 4 – (-4.236)

= 8.236

y = 8-x^-1 =   .236)^-1

= 8.236

x=0.236

  y = 4-x   = 4 – (0.236) = 3.764

y = 8-x^-1 =   8-(0.236)^-1

= 3.764

thus the two lines cross at 2 points:

(-4.236, 8.236) & (0.236, 3.764)

c.   to solve

graphically the equation 4-x = 8-x^-1

we would graph both lines: y = 4-x   and   y

= 8-x^-1

the point on the graph where the lines cross is the

solution to the system of equations.

just graph the points on part b on a cartesian coordinate

system and extend the two lines.   the

solution is, as stated, the point where the two lines cross on the graph.

step-by-step explanation:

mark brainliest!