How to find angles on two line intersect

Hello!

Vertical angles are always congruent

This means that 3x - 35 = 130

We can solve this algebraically

3x - 35 = 130

Add 35 to both sides

3x = 165

Divide both sides by 3

x = 55

The angle AOB and AOC are supplementary which means they add to 180

First we have to find what angle AOB equals

3(55) - 35 = 130

We can subtract 180 by this number to get angle AOC

180 - 130 = 50

Angle AOC is 50

The answers are x = 55 and AOC = 50

Hope this helps!

X^2 - 4x +(4/2^2) + y^2 + 8y + (8/2^2) = -4 + (4/2^2) + (8/2^2)(x + 2)^2 + (y + 4)^2 = -4 + 4 + 16your center is (-2, -4) and the radius is the sqrt of -4 + 4 + 16 which is 4