Astandard number cube is tossed. find p(even or prime).

p(even or prime) =   .

Step-by-step explanation:

Given : A standard number cube is tossed.

To find : find p(even or prime).

Solution : We have given that a cube is tossed.

Total number of number in a cube = 1,2,3,4,5,6

Even number = 2,4,6.

Prime number = 2 , 3, 5.

Probability of even number = =  .

Probability of prime number = =  .

P(A orB) = P(A)+P(B).

Then,

2 is even as well as prime So

p(even or prime) = P(even) +P(prime) - P(2).

p(even or prime) =   +  -

p(even or prime) =  1- .

p(even or prime) =   .

Therefore, p(even or prime) =   .

(0,-3) see attached graph

step-by-step explanation:

a. to solve the system, graph the two equations.

x = y+3 becomes y=x-3 has m=1/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move up 1 unit and 1 unit to the right. plot a point and connect.

y=-4x+3 has m =-4/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move down four units and to the right 1 unit. plot a point and connect.

the solution is the point (x,y) where the two lines intersect. by the graph below it is (0,-3).

b. to solve by substitution, substitute y = -4x-3 into x= y+3

x= (-4x-3) +3

x=-4x

5x=0

x=0

now substitute x = 0 back in to find y.

y= -4(0)-3

y=0-3

y=-3

solution is (0,-3)

c. use elimination by adding the equations together.

x-y=3

4x+y=-3

5x=0

x=0

then substitute into one equation to find y.

y=-4(0)-3

y=-3

answer: 8

step-by-step explanation: if you add the possibilities 5 different flavor and 3 different sizes 5+3=8