The function f(x) is the height of a model rocket x seconds after launch. the rocket reaches its maximum height in 2.5 seconds and hits the ground at 5 seconds. what is the practical domain for the function f(x)?

Time of flight, t = 5 seconds.

From equations of motion,
y = vot - 1/2gt^2
v = vo -gt

At maximum height, v = 0 and t = 2.5 seconds

Therefore,
0 = vo -9.81*2.5 => vo = 9.81*2.5 = 24.525 m/s

Therefore,
f(x) = 24.525t - 1/2gt^2 = 24.525t - 1/2*9.81t = 24.525t - 4.905t^2

In other words, practical domain of f(x) is;
f(x) = 24.525t - 4.905t&2

Answer 20 centimeters15+8=2323-3=20so the answer is 20 centimeters