Antawn jamison is shooting free throws. making or missing free throws doesn't change the probability that he will make his next one, and he makes his free throws 73%, percent of the time. what is the probability of antawn jamison making all of his next 9 free throw attempts?

Probability of Antawn Jamison making all of his next 9 free throw attempts is 0.058 i.e. 5.8%

Step-by-step explanation:

Since we have given that

Probability that he will make his next one and he makes his free throws = 73%

Number of throws = 9

We will use "Binomial distribution":

Hence, probability of Antawn Jamison making all of his next 9 free throw attempts is 0.058 i.e. 5.8%

(0.73)^9

Step-by-step explanation:

Khan Academy

x> 6

step-by-step explanation:

8x+8> 7x+14

8x-7x> 14-8

x> 6

answer: c, the green line

step-by-step explanation:

there is no black line, eliminate b.

simple interest implies periodic payments, but the red line shows no payments, eliminate d.

simple interest has equal payments. if paid say every day, the graph is about a straight line (actually a stairstep).

the yellow line is not straight, eliminate a.

check: the green line is straight, answer is c.

simple interest with positive interest rate gives a straight line sloping up to the right. green line:

g(t) = $100 + ($200-$100) ÷ (20 years) × (t years)

= $100 + (4%/year) × ($100)(t years)

incidentally, the yellow line curving upward represents continuously compounded interest

y = $100 × 2^(t years / (14 assuming the yellow line hits $200 at 14 years. 2^0 is 1, so y(0) = $100; 2^(14/14) is 2, so y(14) = $200.