What two numbers multiply to -96 and add to 7

The numbers are x and y.
Therefore, we can suggest this system of equations:
xy=-96
x+y=7                      ⇒x=7-y
solve this systeme  by substitution method.
(7-y)y=-96
7y-y²=-96
y²-7y-96=0
We solve this square ecuation:
y=[7⁺₋√(49-4(1)(-96))] / 2=(7⁺₋√433)/2

We have two solutions:
y₁=(7-√433)/2    (y₁≈-6.904326...)
x₁=7-y₁
x₁=7-(7-√433)/2=(7+√433)/2      (x₁≈13.904326...)

y₂=(7+√433)/2      (y₂≈13.904326...)
x₂=7-y₂
x₂=7-(7+√433)/2=(7-√433)/2       (x₂≈-6.904326...)

Therefore:
The numbers are (7-√433)/2  and (7+√433)/2.

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