Me answer this question! (25pts) : (

Based from the jar you have 4 R's for red
7 B's for blue, 5 G's for green therefore caculations add up to 16 marbles in total. a. chances of finding a red marble gives you 4 over 16 (4/16) or reduce that and get 1 over 4 (1/4)

Next, the probability of finding a blue marble >> 7 B's = 7/16
cross- multiply the red and blue's possibilities 1 over 4 × 7 over 16 = 7 over 64
yay, now that's your probability for part A

Part B >> again you have 4 over 16 (4/16)  or 1 over 4 (1/4) as your probability for red marble . . 
Next, what is your probability of selecting a blue marble with A RED MARBLE removed. 7/15 << take one red marble to get that 15 instead of 16. 
Now .. final part in this .. you gotta Multiply the probabilities
1 over 4 (1/4) × 7 over 15 (7/15) evaluate that for your answer

C. it wouldn't be equivalent, so No

My answer would be B what is the probability of selecting a red marble and setting it aside and then selecting a blue marable...

there are 7 blue marbles and 4 red marbles and if you randomly pick out a marble it might be red and setting it aside might be blue because there are less red marbles at the top and multiple blue marbles around the jar   

Were is the diagram?