Find the magnitude and direction angle for the vector v = 3 cos 123°i + 3 sin 123°j. a. 3√2, 57° b. 3√2, 123° c. 3, 57° d. 3, 123°

The vector written in its generic form is given by:
 v = lvl cos theta ° i + lvl without theta ° j
 Where.
 lvl: magnitude of the vector
 theta: angle of the vector with respect to the x axis.
 For this case we have the following vector:
 v = 3 cos 123 ° i + 3 without 123 ° j
 Where,
 lvl = 3
 theta = 123 °
 
 The magnitude and direction angle for the vector v is:
 D. 3, 123 °

Th is not an attachment