Find the lateral area the regular pyramid l. a. =

We know that
lateral area=3*[area of a equilateral triangle]
Applying the law of sines to calculate the area of a equilateral triangle
Area=(1/2)*a*b*sin C
a=4
b=4
C=60 degrees
area equilateral triangle=0.5*4*4*sin 60> 0.5*4*4*√3/2---> 4√3 units²
lateral area=3*[4√3]> 12√3 units²

the answer is
12√3 units²

The answer is c. 7 (i think) i’m almost sure though

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