Answers: 1
![x+2+\left[4x-\dfrac{x^2+6x+8}{x+4}\right]=x+2+\left[4x-\dfrac{x^2+4x+2x+8}{x+4}\right]\\\\=x+2+4x-\dfrac{x(x+4)+2(x+4)}{x+4}=5x+2-\dfrac{(x+2)(x+4)}{x+4}\\\\=5x+2-(x+2)=5x+2-x-2=4x](/tpl/images/0111/7556/42c41.png)
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Which expression is equivalent to x+2+ [4x - x2+6x+8\x+4]...
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