Find the area of parallelogram abcd given m a = 30 and the following measures. ab = 10 in.; ad = 6 in. a= 30 in.² 30√3 in.² 60 in.²i would really appreciate the it's for my friend

Ihave attached a screenshot with the diagramanswer: area = 30 in²explanation: area of the parallelogram can be calculated as follows: area = base * heightin the given, we have: base = ab = 10 inheight = ax  > we need to calculate that1- getting the height of the parallelogram (ax): we know that: ax is perpendicular on abmeasure angle dab = 30°this means that: measure angle xad = 90 - 30 = 60°now, in triangle xad, we have: measure angle x = 90°this means that this triangle is a right-angled triangle, therefore, we can apply the special trig functions to get the length of ax as follows: we know that: cos  θ = adjacent / hypotenusewe have: θ = 60°adjacent = ax that we want to findhypotenuse = ad = 6 inthis measn that: cos 60 = ax / 6ax = 6 * cos 60ax = 3 in2- getting the area of the parallelogram: area = base * heightarea = ab * axarea = 10 * 3area = 30 in²hope this : )

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