Graph 2x plus y is less than 7 and state one point in the solution set

2x + y = 7

First, let's get y alone on one side of the equation so we can solve this more easily:
y = 7 - 2x

You can start to plug-in number to graph your equation. For example, if x = 0, than y = ?. Solve for y:

y = 7 - 2 x 0
y = 7

So if x is 0, than y = 7. Now you can plot your first point on the graph: (0, 7)
Now you do it vice versa, if y = 0, x = ?. So solve for x:

0 = 7 - 2x
0 - 7 = -2x
-7 = -2x
-7/-2 = x
7/2 = x

So when y is 0, x ix 7/2; (7/2, 0)

Just keep plugging in number, for example you can plug in numbers going one digit at a time, which is the easiest way; if x = 1, than y = ?, if x = 2, then y = ? etc.

To "state one point in the solution set", I'm not too sure I know what you mean; perhaps it means that you should show the points that helped you draw the line? I'm sure you will be able to answer it if you have understood what I have said.

I've graphed your equation so you can check your work, it should resemble, to some point, the one have drawn. The two red points I have marked are to show that when x = 0, y = 7. (Remember, your y-intercept should be 7 because we already figured out that when x = 0, y = 7). Don't worry is the slope is not as steep as mine, your slope may, in fact, turn out to be less steep and that does not mean it is wrong.

Dm me pls mike and

(-8,5) bu tun not sure ok