Find the center, vertices, and foci of the ellipse with equation 2x2 + 9y2 = 18.

To solve this problem you must apply the proccedure showb below:

 1. You have the following equation:

  2x^2+9y^2=18

 2. Dividing the equation by 18, you have:

 (x^2/9)+(y^2/2)=1

 3. The center is:

 [(x-0)^2/9]3^2[(y-0)^2/√2]=1

 (h,k)=(0,0)

 The center is (0,0)

 4. The vertices are:

 a^2=9
 a=3

 Vertices: (-3,0) and (3,0)

 5. The foci is:

 c^2=a^2-b^2
 c=√7

 The foci is: (-√7,0) and (√7,0)

With a continuous thought process.