Graph y ≥ (x + 2)2 click on the graph until the correct graph appears.

We plug in the values of x and y as shown below:

the given equation is

As we can see the equation is of the form of a parabola . The equation of parabola is given as

in the equation h = -2 and k =0

On plotting the above parabola on graph is as shown on the sheet

The vertex is (h,k) = (-2,0)

The y intercept is (0+2)^2 = 4. So, y intercept is (0,4)

The x intercept in this case is the same as vertex = (-2,0)

Now, we graph the parabola as shown in the attachment

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.

sine

step-by-step explanation: