Easy math problem, .o is the center of the circle. assume that lines appear to be tangent are tangent. what is the value of x? a. 34b. 36.5c. 73d. 107

Option C. 73

Step-by-step explanation:

In the given figure Δ OPQ is the right angle triangle because radius is always perpendicular to the tangent drawn on the circle from an external point.

Here OQ is radius and PO is tangent.

So ∠OQP = 90°

Now sum of all angles of a triangle is 180°

Therefore, ∠OPQ + ∠OQP + ∠POQ = 180°

                  17° + 90° + x° = 180°

                 107 + x = 180

                 x = 180 - 107

                 x = 73°

Option C. 73