The current size of an image on samuel's computer is shown below: a rectangle is shown. the length of the rectangle is labeled as length equal to 8 inches and the width is labeled as width equal to 10 inches. what are the dimensions of the image at fraction 1 over 2 times its current size

The length and the width of image is  4 inches and 5 inches respectively

Step-by-step explanation:

Given : Length of rectangle is 8 inches

          Width of rectangle is 10 inches

To Find: What are the dimensions of the image at fraction times its current size

Solution:

Length of rectangle is 8 inches

Since we are given that the dimensions of the image at fraction times its current size

So, Length of image =

Thus the length of image is 4 inches.

Width of rectangle is 10 inches

Since we are given that the dimensions of the image at fraction times its current size

So, width of image =

Thus the width of image is 5 inches.

Hence the length and the width of image is  4 inches and 5 inches respectively.

there are many solutions.

step-by-step explanation:

step 1: simplify both sides of the equation.

4x+6=4x^2+10x−4

step 2: subtract 4x^2+10x-4 from both sides.

4x+6−(4x^2+10x−4)=4x^2+10x−4−(4x^2+10x−4)

−4x^2−6x+10=0

step 3: factor left side of equation.

−2(2x+5)(x−1)=0

step 4: set factors equal to 0.

x=-5/2 or x=1

add the table and i will answer correctly

step-by-step explanation: