3.) If I have 45L of helium in a balloon at 300K and increase the temperature of the balloon to 350K, what will the new volume of the balloon be?

V1:

T1:

V2:

T2:

V1 is volume 1 T1 is temperature 1 V2 is volume 2 T2 is temperature 2 so there fore V1 would be 45L T1 would be 300k V2 is unknown T2 is 350k your formula should be 350k is 50k more then 300k so 300k divided by 50k = lets say it =x then u take 45L divided by x then u get lets say its b then u take b and add it to 45 to get answer

Explanation:

if 300k temp is 45L then u find how much volume each 50k temp is bc 350k is 50k more then 300k so then after finding how much volume the balloon has per 50k temp u add that to the original volume and find the new one if you don't understand my thinking or need further explanation or questions let me know.

18+220=238 fruits together

explanation:

but are you serious?

i dont think so i think its more a lot of people i know failed the first time

explanation: