History
History, 20.05.2021 01:00, hdbvhf

Substitutex=cos\alp,\alp∈[0:;π] T
h
e
n

x
+
1

x
2

=
2
(
2
x
2

1
)
\Leftright

c
o
s
\alp
+
s
i
n
\alp

=
2
(
2
c
o
s
2
\alp

1
)
Then∣x+
1−x
2


∣=
2

(2x
2
−1)\Leftright∣cos\alp+sin\alp∣=
2

(2cos
2
\alp−1)

N
2
c
o
s
(
\alp

π
4
)

=
N
2
c
o
s
(
2
\alp
)
\Right
\alp

[
0
;
π
4
]

[
3
π
4
;
π
]
∣N
2

cos(\alp−
4
π

)∣=N
2

cos(2\alp)\Right\alp∈[0;
4
π

]∪[
4


;π]
1)
\alp

[
0
;
π
4
]
\alp∈[0;
4
π

]
c
o
s
(
\alp

π
4
)
=
c
o
s
(
2
\alp
)

cos(\alp−
4
π

)=cos(2\alp)…
2.
\alp

[
3
π
4
;
π
]
\alp∈[
4


;π]

c
o
s
(
\alp

π
4
)
=
c
o
s
(
2
\alp
)

−cos(\alp−
4
π

)=cos(2\alp)…

this is joke just answer 1+1

answer
Answers: 1

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Substitutex=cos\alp,\alp∈[0:;π] T
h
e
n

x
+
1
−<...

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