History, 20.04.2021 19:00, toribrown3773

What role did the rise in fascism have in the outbreak of WWII?

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The rise of fascism in Italy began during World War I, when Benito Mussolini and other radicals formed a political group (called a fasci) supporting the war against Germany and Austria-Hungary.The first meeting of Mussolini’s Fasci of Revolutionary Action was held on January 24, 1915.For the next several years, the small group of fascists took part in political actions, taking advantage of worker strikes to incite violence.Around 1921, the fascists began to align themselves with mainstream conservatives, increasing membership exponentially.Beginning in 1922, Fascist paramilitaries escalated their strategy from attacking socialist offices and homes of socialist leadership figures to violent occupation of cities, eventually setting their sites on Rome.During the so-called “March on Rome,” Mussolini was appointed Prime Minister of Italy.

From 1925 to 1929, Fascism steadily became entrenched in power. Opposition deputies were denied access to parliament, censorship was introduced, and a December 1925 decree made Mussolini solely responsible to the King.

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answered: Guest

$\text{the answer is b. } \frac{31}{4}$

step-by-step explanation:

$\newline{\text{note: this is my first question where i fully use latex throughout the answer}}$ $\bigskip\bigskip\bigskip\newline\text{the equation of an aritmetic sequence is } a_n=a_1+d(n-1) \text{ where}$ $\medskip\newline{a_n \text{ is the nth term}}$ $\bigskip\newline{a_1 \text{ is the first term}}$ $\medskip\newline{d \text{ is the common difference} (\text{ note: } a_n-a_{n-1}=d)}$ $\newline{\text{n is which term it is}}$ $\bigskip\newline{\text{given that the sequence is } -\frac{3}{4}, -\frac{2}{3}, -\frac{7}{12}, -\frac{1}{2}{ we must find } a_1 \text{ and } d}$ $\bigskip\newline{\text{the first term is } -\frac{3}{4}}$ $\newline{\text{if we find their differences by making them all have a common denomenator, we find that the common difference is } \frac{1}{12}}$ $\newline{\text{therefore, the 103rd term is }a_{103}=-\frac{3}{4}+\frac{1}{12}(103-1)}\newline{a_{103}=-\frac{3}{4}+\frac{1}{12}(102)}$ $\newline{a_{103}=-\frac{3}{4}+\frac{102}{12}}$ $\newline{a_{103}=-\frac{9}{12}+\frac{102}{12}}$ $\newline{a_{103}=\frac{93}{12}}$ $\newline{a_{103}=\frac{31}{4}}$ $\newline{\text{therefore the 103rd term is }\frac{31}{4}}$ $\newline{\text{the answer is b. } \frac{31}{4}}$