In the presidential election of 1824, andrew jackson

When the election was held on November 9, 1824, Jackson obtained 151,363 votes (other sources speak of up to 153,544 votes) that represented 41.36% of the popular votes; while Adams obtained between 108,740 and / or 113,142 votes (around 30.92% of the popular vote); Clay came third in popular suffrage with 47,545 votes or 47,136 (12.99% of the popular vote); and Crawford was the least voted with 41,032 votes or 46,618 (11.21% of that popular suffrage). Another 6,616 popular votes (1.81%) went to nominees for Democratic-Republican electors not previously committed to any presidential candidate; and 6,230 popular votes (1.70%) to other options.

In the Electoral College the results were Andrew Jackson with 99 votes; John Quincy Adams followed with 84; William Harris Crawford, 41; and Henry Clay, 37.

Although, as has already been mentioned, none officially obtained a necessary majority to take over the presidency, so the election came to the hands of the House of Representatives.

Explanation:

The presidential elections of 1824 were going to suppose a radical change in the historical political line of the United States to date. John Quincy Adams was elected president on February 9, 1825. The previous years had been a one-party government in the United States, as the Federalist Party was dissolved, this election would only present the Democratic-Republican Party, with the peculiarity that there were 4 candidates separately who sought the presidency. The faction led by Andrew Jackson would evolve in the Democratic Party, while the factions led by John Quincy Adams and Henry Clay, would become the National Republican Party, and later in the Whig Party.

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Explanation:

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