Health, 17.10.2020 20:01, iilovejohnccena1022
Given the function g(x) = 41x3 + a for some constant a, which describes the inverse function gā1(x)?
no restriction on the domain of g(x); inverse is gā1(x) = RootIndex 3 StartRoot StartFraction x minus a Over 41 EndFraction EndRoot
no restriction on the domain of g(x); inverse is gā1(x) = (StartFraction x minus a Over 41 EndFraction) cubed
domain of g(x) restricted to x ā„ 0; inverse is gā1(x) = RootIndex 3 StartRoot StartFraction x minus a Over 41 EndFraction EndRoot
domain of g(x) restricted to x ā„ 0; inverse is gā1(x) = (StartFraction x minus a Over 41 EndFraction) cubed
Answers: 2
, we are to find the inverse of the function a shown below:
![x = 41y^3+a\\41y^3 = x-a\\y^3 = \frac{x-a}{41} \\y = \sqrt[3]{\frac{x-a}{41} }](/tpl/images/0816/4949/858f7.png)
![g^{-1}(x) = \sqrt[3]{\frac{x-a}{41} }](/tpl/images/0816/4949/777de.png)
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Given the function g(x) = 41x3 + a for some constant a, which describes the inverse function gā1(x)?...
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