The specific heat of ice is 0.492 cal/ (g × °c). how many calories of heat are required to raise 100.0 g of ice from -20.0°c to -0.5°c?

For this case we have that the number of calories is given by the following equation:

C = mCpΔt

Where,

m: mass

Cp: specific heat

Δt : temperature differential

Substituting values we have:

Around 959.4 calories of heat are required to raise 100.0 g of ice from -20.0 ° c to -0.5 ° c

ia. mver.y..sor .r..yinee..i am.ina.rush.pleas eforg.ive   meiknowiama. nas.s holei apalo.gize

the ecg findings of an acute anterior myocardial infarction wall include: st segment elevation in the anterior leads (v3 and v4) at the j point and sometimes in the septal or lateral leads, depending on the extent of the mi. this st segment elevation is concave downward and frequently overwhelms the t wave.

explanation: