Given: ΔABC with AD:DB = CE:EB Prove DE||AC 1. AD:DB = CE:EB Given

2. AD:DB+1 = CE:EB+1 Addition Property of Equality

3. (AD+DB)/DB = (CE+EB)/EB Using common denominators

4. AB = AD+ DB and CB = CE +EB segment addition

5. AB:DB = CB:EB Substitution property of equality

6. [Fill in missing statement from choices below] Reflexive property of congruence

7. ΔABC ~ ΔDBE SAS similarity criterion

8. ∠BAC ≅ ∠BDE Corresponding angles of similar triangles are congruent.

9. DE||AC If the corresponding angles formed by two lines cut by a transversal are congruent, then the lines are parallel.

What is the missing step in this proof?

A. ∠ABC ≅ ∠DBE

B. ∠BCA ≅ ∠BDE

C. ∠ACB ≅ ∠DEB

D. ∠BDE ≅ ∠ADE

E. ∠CAB ≅ ∠DAC

I got this wrong on the test and I don't know what I did wrong.