Find the equivalent thickness of co2 on earth.

earth’s atmospheric co2 = 3.2 × 1015 kg

earth’s radius = 6.4 × 106 m

molar volume (@stp) = 22.414 l mol-1

h = 9483 m

Explanation:

Assume Re as radius of earth and h as equivalent thickness of co_2

total volume occupied by

mass of

1 mole of co_2 has  44 g mass

1 g has = 1/44 mole

total volume by

SOLVING RIGHT SIDE WE GET

solving for h we get

h = 9483 m

the answer is "c" im pretty sure.