Ok so, we have a triangle where it goes up to 90°, AB = 10.9mm and BC = 23.6mm. what is AC?
give the answer in one decimal ​

In triangle ABC,

∠BAC = 90°,

Thus by the Pythagoras theorem,

BC^2=AB^2 + CA^2

We have,

AB = 9.6 mm and CA = 7.6 mm,

By substituting the values,

BC^2 = 9.6^2 + 7.6^2 =92.16+ 57.76= 149.92

\implies BC = 12.24418\approx 12.2\text{ mm}

Explanation:

I found this helpful from Gungunbajpai

the correct answer is:   [d]:

              →       " fond of fighting " .

hope this !

      best wishes!

a i thinkmark me brainliest