Engineering, 09.11.2021 20:10, gamergladiator43
The following cost and benefit information has been estimated for a pump that has a 10-year useful life.
Purchase Cost = $2,400
Annual Operating Cost = $1,200
Annual Maintenance Cost = $300
Annual Benefits = $2,000
Salvage Value = $200
Interest rate specified = 9% or 0.09
Find the capital recovery cost for this pump.
Answers: 3
Engineering, 04.07.2019 18:20, 1230bering
Select any two (2) areas of applications of chain-drive. (clo4) a)-permanent lubrication necessary b)-hydraulic forklift truck operation c)-rigging and heavy moving materials d)-relatively high maintenance costs e)-costlier than belt drives
Answers: 2
Engineering, 04.07.2019 19:20, horsedoggal1234
Consider airflow over a flat plate of length l = 1.5 m under conditions for which transition occurs at le = 0.9 m based on the critical reynolds number, re, e = 5 x 10. evaluating the thermophysical properties of air at 400 k, determine the air velocity. (hint: use the tables to find the properties of air)
Answers: 3
Engineering, 04.07.2019 19:20, natalie2sheffield
Acompressor compresses a gas, a pump compresses a liquid. for a given pressure ratio, why does it take more work to compress a gas in a compressor than a liquid in a pump? a)- for a given pressure ratio the average specific volume for a gas is much higher than the average specific volume for a liquid. b)- there is no difference. the only difference is the amount of heat generated (not work) c)- for a given pressure ratio the average volurge for a gas is much higher than the average volume for a liquid. d)-there is no difference
Answers: 3
The following cost and benefit information has been estimated for a pump that has a 10-year useful l...
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