The current at resonance in a series L-C-R circuit is 0.2mA. If the applied voltage is 250mV at a frequency of 100 kHz and the circuit capacitance is 0.04 microfrad . Find the circuit resistance and inductance

Explanation:

Given;

current at resonance, I = 0.2 mA

applied voltage, V = 250 mV

resonance frequency, f₀ = 100 kHz

capacitance of the circuit, C = 0.04 μF

At resonance, capacitive reactance () is equal to inductive reactance (),

Where;

R is the resistance of the circuit, calculated as;

The inductive reactance is calculated as;

The inductance is calculated as;

answer:

put more,

answer:

it will water down the soup lol

explanation: