Consider a slab of material containing a volume charge distribution throughout. The slab is of length d in the z direction, and its dimensions in x and y represent a cross-sectional area of A. Free space permittivity exists throughout. The electric field in the slab is given by E = 6.aexp(-az) a, V/m where po is a positive constant. (a) Find the volume charge density p, in the slab. (b) Find the total charge in the slab. (c) Verify your result for part b by evaluating the net outward flux of D through the slab surfaces.

answer:

yes

explanation:

answer: Yes

Explanation:

answer:

// here is code in C++.

#include <bits/stdc++.h>

using namespace std;

//main function

int main()

{

  // variable

 int n;

 cout<<"enter a number:";

 // read the input

 cin>>n;

 // find the square root of the absolute value

 float square_root=sqrt(abs(n));

 // print the square_root

 cout<<"square root of "<<n<<" is: "<<square_root<<endl;

  return 0;

}

Explanation:

Read a number from user and assign it to "n".Then find its absolute value with abs() function.Then calculate the square root of the absolute value with sqrt() function.Print the square root of the number.

Output:

enter a number:-17

square root of -17 is: 4.12311

                                                         This is easy

                                                     sinserly Natalie 7 grader (this is not that hard)