The following are cross-section notes for a transition from cut to fill. The roadbed is 12 m wide in cut and 14 m wide in fill. Side slopes are 1:2. Compute volumes of cut and fill by the average end area method or pyramid volume as appropriate. Find the net amount of waste or borrow, allowing 12% shrinkage for material excavated and placed in embankments. Borrow should be expressed in fill meters and waste in cut meters.

answer:

c

explanation:

answer:

// here is code in C++.

#include <bits/stdc++.h>

using namespace std;

//main function

int main()

{

  // variable

 int n;

 cout<<"enter a number:";

 // read the input

 cin>>n;

 // find the square root of the absolute value

 float square_root=sqrt(abs(n));

 // print the square_root

 cout<<"square root of "<<n<<" is: "<<square_root<<endl;

  return 0;

}

Explanation:

Read a number from user and assign it to "n".Then find its absolute value with abs() function.Then calculate the square root of the absolute value with sqrt() function.Print the square root of the number.

Output:

enter a number:-17

square root of -17 is: 4.12311

                                                         This is easy

                                                     sinserly Natalie 7 grader (this is not that hard)