Engineering, 12.08.2020 06:01, blevinssam274
A 4.2-mm-diameter proton beam carries a total current of 1.2 mA . The current density in the proton beam, which increases with distance from the center, is given by J=Jedge(r/R) , where R is the radius of the beam and Jedge is the current density at the edge.
Required:
a. How many protons per second are delivered by this proton beam?
b. Determine the value of Jedge.
Answers: 3
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A 4.2-mm-diameter proton beam carries a total current of 1.2 mA . The current density in the proton...
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