A hollow shaft of diameter ratio 3/8 (internal dia to outer dia) is to transmit 375 kW power at 100 rpm. The maximum torque being 20% greater than the mean torque. The shear stress is not to exceed 60 N/mm2 and twist in a length of 4m not to exceed 2o. Calculate its external and internal diameters which would satisfy both the above conditions. (G= 0.85 X 105 N/mm2)
A) SOBDM/BCCM (I Think)
See the attachment
Connecting a resistor in series with battery will cause the battery voltage to drop.
voltage across resistor= 12-3.6= 8.4
Current in the circuit= 0.15A
From the bunch of resistors, I will make a combination of 56Ω
A gamma distribution also falls from the class of distributions with waiting times such as exponential spread. When the gamma form parameter is equal to one, otherwise it is exponential. Using the chi-square function it's simple to measure the probability of gamma variables.
The probability that a transistor will last between 10 and 20 weeks is calculated as follows:
Hence, the probability that a transistor will last between 10 and 20 weeks is 0.43.
a)R= sqrt( wt³/12wt)
c)R= sqrt ( wt³/12xcos45xwt)
Thickness = t
Width = w
Length od diagonal =sqrt (t² +w²)
Area of raectangle = A= tW
Radius of gyration= r= sqrt( I/A)
Moment of inertia in the direction of thickness I = w t³/12
R= sqrt( wt³/12wt)
Moment of inertia in the direction of width I = t w³/12
Moment of inertia in the direction of diagonal I= (w t³/12)cos 45=( wt³/12)x 1/sqrt (2)
R= sqrt ( wt³/12xcos45xwt)