Engineering, 05.07.2020 16:01, robert7248
A steady 4.0-lb force is applied normal to the handle of the hand-operated grinder. The gear inside the housing with its shaft and attached handle together weigh 4.26 lb and have a radius of gyration about their axis of 2.97 in. The grinding wheel with its attached shaft and pinion (inside housing) together weigh 1.07 lb and have a radius of gyration of 1.95 in. If the gear ratio between gear and pinion is 5:1, calculate the speed N (in revolutions/min) of the grinding wheel after 5 complete revolutions of the handle starting from rest.
Answers: 1
gain in potential energy as a result of restoring friction
= kinetic energy as a result of rotation of the gear housing
= Kinetic energy as a result of rotation of pinion housing
![4.0*\dfrac{6.0}{12}*5*2 \pi =[ (\dfrac{1}{2}*(\dfrac{4.26}{32.2})*(\dfrac{2.97}{12})^2*(\dfrac{\omega}{5})^2+( \dfrac{1}{2})*(\dfrac{1.07}{33.2}) *(\dfrac{1.95}{12})^2* \omega ^2)]](/tpl/images/0701/8136/59651.png)
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A steady 4.0-lb force is applied normal to the handle of the hand-operated grinder. The gear inside...
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