The center-to-center distance from reference hole A to hole B is 3.00"+/-0.11". Hole A will be ø(4.0"+/-0.1"). If a jig is to be used to locate hole B by inserting a locator pin in hole A of ø(3.85"+/-0.05"), due to the slack between the jig locator pin and hole A: a. What are the potential limits in the location of hole B? b. Are these potential limits acceptable? c. If the potential limits are not acceptable, how would you make them acceptable? In part c, a bushing will be used to make hole B. What should be the specification for bushing location tolerance?

answer: jesus loves you

explanation:

answer:

a

explanation:

answer:

// here is code in C++.

#include <bits/stdc++.h>

using namespace std;

//main function

int main()

{

  // variable

 int n;

 cout<<"enter a number:";

 // read the input

 cin>>n;

 // find the square root of the absolute value

 float square_root=sqrt(abs(n));

 // print the square_root

 cout<<"square root of "<<n<<" is: "<<square_root<<endl;

  return 0;

}

Explanation:

Read a number from user and assign it to "n".Then find its absolute value with abs() function.Then calculate the square root of the absolute value with sqrt() function.Print the square root of the number.

Output:

enter a number:-17

square root of -17 is: 4.12311

                                                         This is easy

                                                     sinserly Natalie 7 grader (this is not that hard)