A hydraulic jump occurs in a 15-m wide rectangular, concrete channel. The initial (normal) depth comes from a spillway discharge of 100 m^3/s with a slope of 10%. The sequent depth is 3.00 m.
Determine the energy loss and the specific force per unit width of the channel.

The head loss = 0.1357 m

The energy loss per unit width of the channel is 3.252 m

The Specific force per unit width of the channel, is 6.01 m²

Explanation:

Here, the slope is 10 %, therefore for every one unit traveled vertically we have 10 units traveled horizontally

Therefore when the depth is 3.00 m, we can select the initial depth as the reference = 1.00 m

We have V₁ = 100 m³/s ÷ (15×1) =  20/3 m/s

V₂ = 100 m³/s ÷ (15×3) =  20/9 m/s

= -0.1357

y₂ - y₁ = 2.00 m  

We have energy loss per unit width of the channel give by

Where:

q = Unit discharge = Q/b = 20/3

b = Widtjh of the chammel

Therefore

= 3.252 m

The specific force per unit width of the channel is given by

Where:

= Specific force per unit width of the channel

 = 6.01 m²

answer: 500 wph.

explanation: