The switch in the circuit has been closed for a long time and is opened at t = 0.

a. Calculate the initial value of i.

b. Calculate the initial energy stored in the inductor.

c. What is the time constant of the circuit for t > 0?

d. What is the numerical expression for i(t) for t ≥ 0?

e. What percentage of the initial energy stored has been dissipated in the 4 Ω resistor 5ms after the switch has been opened?

a) i=-16A

b) E=1.28 J

c) T=2.5 m

d) i(t)=-16e^(-400*t)

e) E=1.26 J

Explanation:

The circuit is shown in the attached diagram:

a) at t=0, the circuit is in steady state and we have the following:

Clearing V:

V=80 V

b) the initial energy stored is equal to:

c) at t>0

d) if t=∝, i=0

for t≥0

e) the energy disipation in 4Ω is equal to:

answer:

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