Engineering, 23.03.2020 16:52, cougs
A 15° half-wedge is inserted into a wind tunnel at 0° angle of attack. When the tunnel is operating, the wave angle from the wedge leading edge is 48°. What is the exit-to-throat area ratio of the tunnel nozzle?
Answers: 3
is 1.556.![\frac{A}{A*} = \frac{1}{M} [(\frac{2}{k+1})(1+\frac{k-1}{2}M^2)]^{\frac{(k+1)}{[2(k-1)]} }](/tpl/images/0558/9004/2474c.png)
= Throat area![\frac{A}{A*} = \frac{1}{1.9} [(\frac{2}{1.4+1})(1+\frac{1.4-1}{2}1.9^2)]^{\frac{(1.4+1)}{[2(1.4-1)]} }](/tpl/images/0558/9004/f907c.png)
= 1.556.
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A 15° half-wedge is inserted into a wind tunnel at 0° angle of attack. When the tunnel is operating,...
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