A capacitor in an RC circuit with R = 2 Ω and C = 4 F is being charged. The time required for the capacitor voltage to reach 63.2 percent of its steady-state value is: Group of answer choices 2 s 4 s 8 s 16 s

Given values are:

As we know the formula,

→ Time taken,

By substituting the above values, we get

Thus the above response i.e., "option c" is right.

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Given Information:

Resistance = R = 2 Ω

Capacitance = C = 4 F

Required Information:

Time constant = τ = ?

τ = 8 seconds

Explanation:

one time constant τ is the amount of time taken when the capacitor chargers up to approximately 63 % of its maximum possible voltage.

τ = RC

τ = 2*4

τ = 8 seconds

So that means after 1 τ (8 seconds) the capacitor voltage will reach approximately 63.2 % of its maximum possible voltage.