Use a Karnaugh map to build a circuit that receives 4 inputs A3, A2, A1, A0 and outputs 1 if either A3 ≥ A2 ≥ A1 ≥ A0 or A3 ≤ A2 ≤ A1 ≤ A0. Otherwise the output is 0. For example on input A3A2A1A0 = 0111 the output will be 1, on input A3A2A1A0 = 1100 the output will be 1, and on input A3A2A1A0 = 0101 the output will be 0. You are required to represent the function using a Karnaugh Map, to derive a simplified algebraic expression using the K-map, and to implement (i. e., draw) the corresponding circuit. You may use MUXs and/or decoders in your circuit implementation.