Aluminum bar, 10 cm in diameter, 1 m long, 1 mm thickness Modulus of Elasticity = 70 GPa – Yield Stress = 280 MPa Coefficient of Thermal Expansion = 25 µm/m°C The bar is perfectly clamped at is outer edges, preventing any deformation. The initial temperature is 20°C. What is the stress in the bar if (is it tension or compression?):  Cooled to 0°C  Reheated to 20°C  Further heated to 100°C  Cooled to 20°C  Further cooled to ‐200°C  Reheated to 20°C

i mean i gues

explanation:

answer:

// here is code in C++.

#include <bits/stdc++.h>

using namespace std;

//main function

int main()

{

  // variable

 int n;

 cout<<"enter a number:";

 // read the input

 cin>>n;

 // find the square root of the absolute value

 float square_root=sqrt(abs(n));

 // print the square_root

 cout<<"square root of "<<n<<" is: "<<square_root<<endl;

  return 0;

}

Explanation:

Read a number from user and assign it to "n".Then find its absolute value with abs() function.Then calculate the square root of the absolute value with sqrt() function.Print the square root of the number.

Output:

enter a number:-17

square root of -17 is: 4.12311

                                                         This is easy

                                                     sinserly Natalie 7 grader (this is not that hard)