Engineering, 18.02.2020 22:02, LilFabeOMM8397
A specimen of aluminum having a rectangular cross section 9.6 mm × 12.4 mm (0.3780 in. × 0.4882 in.) is pulled in tension with 35000 N (7868 lbf) force, producing only elastic deformation. The elastic modulus for aluminum is 69 GPa (or 10 × 106 psi). Calculate the resulting strain.
Answers: 2
= Young's modulus
= force applied on the material
= cross-sectional area
= length of the material
= elongation due to stress applied
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A specimen of aluminum having a rectangular cross section 9.6 mm × 12.4 mm (0.3780 in. × 0.4882 in.)...
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