Engineering, 18.02.2020 04:53, ElegantEmerald
A large V8 SI four-stroke cycle engine with a displacement of 4.6 liters is equipped with cylinder cutout, which converts the engine to a 2.3 liter V4 when less power is needed. At a speed of 1750 RPM the engine, as a V8, has a volumetric efficiency of 51%, a mechanical efficiency of 75%, an air-fuel ratio of 14.5, and produces 32.4 kW of brake power using gasoline. With cylinder cutout and operating at higher speed as a V4, the engine has a volumetric efficiency of 86%, a mechanical efficiency of 87%, and uses an air-fuel ratio of 18.2. Indicated thermal efficiency can be considered the same at all speeds, and assume combustion efficiency is 100%. Calculate: a. Mass flow rate of air into V8 engine at 1750 RPM (kg/s). b. Mass flow rate of fuel into V8 engine at 1750 RPM (kg/s). c. The BSFC as V8 at 1750 RPM (g/kW-hr). d. The engine speed needed as a V4 to make the same brake power as a V8 (RPM). e. The BSFC as V4 at the higher speed (g/kW-hr).
Answers: 1
Engineering, 04.07.2019 18:10, Larkinlover703
Items are similar to the free issue items, but their access is limited. (clo5) a)-bin stock items free issue b)-bin stock controlled issue c)-critical or insurance spares d)-rebuildable spares e)-consumables
Answers: 1
Engineering, 04.07.2019 19:10, nbunny7208
What is the chief metrological difference between measuring with a microscope and with an electronic comparator? a. the microscope is limited to small workpieces. a. the microscope is limited to small workpieces. c. the comparator can only examine one point on the workpiece. d. the microscope carries its own standard.
Answers: 1
A large V8 SI four-stroke cycle engine with a displacement of 4.6 liters is equipped with cylinder c...
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