Engineering, 12.02.2020 23:12, summerdooleyu
The velocity of a particle is given by v=16t^2i+4t^3j+(5t+2k) m/s, where t is in seconds. if the particle is at the origin when t=0, determine the magnitude of the particle's acceleration when t=2s. also what is the x, y,z coordinate position of the particle at this instant
Answers: 2
![a_{x}=\frac{d}{dt} v_{x}=\frac{d}{dt}[16t^{2}]=32t\\a_{y}=\frac{d}{dt} v_{y}=\frac{d}{dt}[4t^{3}]=12t^{2} \\a_{z}=\frac{d}{dt} v_{z}=\frac{d}{dt}[5t+2]=5](/tpl/images/0509/0979/b9b50.png)
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The velocity of a particle is given by v=16t^2i+4t^3j+(5t+2k) m/s, where t is in seconds. if the par...
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