The real power delivered by a source to two impedances, =4+⁡ω and =10⁡ω connected in parallel, is 1000 w. determine (a) the real power absorbed by each of the impedances and (b) the source current.

The question is incomplete, below is the complete question

"The real power delivered by a source to two impedance, Z1=4+j5⁡Ω and Z2=10⁡Ω connected in parallel, is 1000 W. Determine (a) the real power absorbed by each of the impedances and (b) the source current."

a. 615W, 384.4W

b. 17.4A

Explanation:

To determine the real power absorbed by the impedance, we need to find first the equivalent admittance for each impedance.

recall that the symbol for admittance is Y and express as

Hence for each we have,  

for the second impedance we have

we also determine the voltage cross the impedance,

P=V^2(Y1 +Y2)

The real power in the impedance is calculated as

for the second impedance

b. We determine the equivalent admittance

We convert the equivalent admittance back into the polar form

the source current flows is

answer:

truck

explanation:

its a truck maybe cause a rv is like a truck and yea but plz mark brainlest!